JetBrains的推广活动，解谜后可以获取三个月的免费订阅。由于是推广活动，所以解密过程不是非常难。真正让人头痛的是那糟糕的网速，不管挂不挂代理页面的打开都非常的慢。
题目一
48 61 76 65 20 79 6f 75 20 73 65 65 6e 20 74 68 65 20 73 6f 75 72 63 65 20 63 6f 64 65 20 6f 66 20 74 68 65 20 4a 65 74 42 72 61 69 6e 73 20 77 65 62 73 69 74 65 3f
解题
很明显字符串的ASCII码，使用python很容易进行解码
>>> s = "48 61 76 65 20 79 6f 75 20 73 65 65 6e 20 74 68 65 20 73 6f 75 72 63 65 20 63 6f 64 65 20 6f 66 20 74 68 65 20 4a 65 74 42 72 61 69 6e 73 20 77 65 62 73 69 74 65 3f"
>>> ''.join(chr(int(e, 16)) for e in s.split(' '))
'Have you seen the source code of the JetBrains website?'
题目二
查看首页源代码找到解谜线索
JetBrains has a lot of products, but there is one that looks like a joke on our Products page, you should start there... (hint: use Chrome Incognito mode)
It’s dangerous to go alone take this key: Good luck! == Jrrg#oxfn$
根据提示，到产品页面。其中名为“JK”的产品介绍是“dare to lean more”，点击该产品继续进行挑战。
注：之前都不知道JetBrains居然已经有这多的产品了。
题目三
补完 https://jb.gg/### 后面确实的三个数字。数字为500到5000的质数个数。
解题
到网上找了个求质数的函数，跑了一下，很快得到结果574
import math
def isprime(n):
if n < 2:
return False
for i in range(2, int(math.sqrt(n)) + 1):
if n % i == 0:
return False
return True
count = 0
for i in range(500, 5000):
if isprime(i):
count += 1
print(count)
题目四
打开上面得到的链接，其中有张图片。图片中的字符为“MPS-31816”
解题
这个题目最坑的在于这个图片实在是太大了，约有15M，死活打不开。
- 查看图片属性，用编辑器直接打开图片，都没有获取到有效的信息。
- 直接访问
https://www.jetbrains.com/MPS-31816显示没有这个网页。 - 于是直接启用Google搜索
MPS-31816在JetBrains 网站找到对应页面。注：后续会知道图片上的图标是JebBrains网站的问题区的Logo。
题目五
“The key is to think back to the beginning.” – The JetBrains Quest team
Qlfh$#Li#|rx#duh#uhdglqj#wklv#|rx#pxvw#kdyh#zrunhg#rxw#krz#wr#ghfu|sw#lw1#Wklv#lv#rxu#lvvxh#wudfnhu#ghvljqhg#iru#djloh#whdpv1#Lw#lv#iuhh#iru#xs#wr#6#xvhuv#lq#Forxg#dqg#iru#43#xvhuv#lq#Vwdqgdorqh/#vr#li#|rx#zdqw#wr#jlyh#lw#d#jr#lq#|rxu#whdp#wkhq#zh#wrwdoo|#uhfrpphqg#lw1#|rx#kdyh#ilqlvkhg#wkh#iluvw#Txhvw/#qrz#lw“v#wlph#wr#uhghhp#|rxu#iluvw#sul}h1#Wkh#frgh#iru#wkh#iluvw#txhvw#lv#‟WkhGulyhWrGhyhors†1#Jr#wr#wkh#Txhvw#Sdjh#dqg#xvh#wkh#frgh#wr#fodlp#|rxu#sul}h1#kwwsv=22zzz1mhweudlqv1frp2surpr2txhvw2
解题
很明显要用到之前的 take this key: Good luck! == Jrrg#oxfn$ 。我一开始将问题想的太复杂了，以为第一题里的内容是密钥，用xor进行解密。在网上找了个xor解密的函数，解出来一塌糊涂。
由回头仔细看了一下这所谓的密码，其实就是一个简单的字映射。
>>> s = "Qlfh$#Li#|rx#duh#uhdglqj#wklv#|rx#pxvw#kdyh#zrunhg#rxw#krz#wr#ghfu|sw#lw1#Wklv#lv#rxu#lvvxh#wudfnhu#ghvljqhg#iru#djloh#whdpv1#Lw#lv#iuhh#iru#xs#wr#6#xvhuv#lq#Forxg#dq
g#iru#43#xvhuv#lq#Vwdqgdorqh/#vr#li#|rx#zdqw#wr#jlyh#lw#d#jr#lq#|rxu#whdp#wkhq#zh#wrwdoo|#uhfrpphqg#lw1#|rx#kdyh#ilqlvkhg#wkh#iluvw#Txhvw/#qrz#lw“v#wlph#wr#uhghhp#|rxu#iluvw#s
ul}h1#Wkh#frgh#iru#wkh#iluvw#txhvw#lv#‟WkhGulyhWrGhyhors†1#Jr#wr#wkh#Txhvw#Sdjh#dqg#xvh#wkh#frgh#wr#fodlp#|rxu#sul}h1#kwwsv=22zzz1mhweudlqv1frp2surpr2txhvw2"
>>>
>>> c = ord('J') - ord('G')
>>> ''.join(chr(ord(e) - c) for e in s)
'Nice! If you are reading this you must have worked out how to decrypt it. This is our issue tracker designed for agile teams. It is free for up to 3 users in Cloud and for 10
users in Standalone, so if you want to give it a go in your team then we totally recommend it. you have finished the first Quest, now it’s time to redeem your first prize. Th
e code for the first quest is “TheDriveToDevelop”. Go to the Quest Page and use the code to claim your prize. https://www.jetbrains.com/promo/quest/'